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Find distance of Champagne cork

  • #1

Homework Statement


A champagne bottle (diameter = 0.014 m) rests on its side on top of a frictionless table. The cork pops and the bottle slides backwards a distance of 0.3 meters in 0.72 seconds. If the bottle’s mass is 500 times greater than the cork’s mass, find the distance from the original position the cork will land on the table.

M= Bottle mass
m= cork mass

Homework Equations


vbottle=d/t
pbottle=Mv

The Attempt at a Solution


vbottle= (.3m)/(.72s)= .42m/s
pbottle= (.5kg)(.42 m/s) = .21 kg m/s

Obviously, I substituted M for .5kg making m= .001kg.

This is where I got stuck and I just need someone to help me with my next equation. From there I should be able to get through this.

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
1,137
0
use conservation of momentum
 
  • #3
Thanks, cupid.

Using CoM I got:

0kg m/s + 0kg m/s = (.21kg m/s) + pc, f
pc, f = -.21kg m/s

p=mv
-.21kg m/s = (.001kg)(v)
v = -210m/s

v = vi + at
-210m/s = 0m/s + (-9.8m/s2)(t)
21.43s = t

x = xi + vit + 1/2 a t2
x = 0m + 0m/s(21.43s) + 1/2 (9.8m/s2)(21.43s)
x = 2550.3m
 
Last edited:
  • #4
1,137
0
Nice ;)
 

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