Linear Collisions: Find Max Compression of Spring

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SUMMARY

The discussion centers on calculating the maximum compression of a spring during a collision between two blocks, where block m1 (2.0 kg) moves at 10 m/s and block m2 (5.0 kg) moves at 3 m/s. The spring has a constant of k = 1120 N/m. Key equations include momentum (p=mv) and kinetic energy (KE=1/2mv^2, KE=1/2kx^2). The solution involves using conservation of momentum and energy principles, particularly focusing on the center of mass system during the collision.

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  • Knowledge of Hooke's law and spring mechanics
  • Ability to analyze systems in the center of mass frame
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Homework Statement


A block of mass m1=2.0 kg slides along a frictionless table with a speed of 10 m/s. Directly in front of it, and moving in the same direction, is a block of mass m2=5.0 kg moving at 3 m/s. A massless spring with spring constant k = 1120 nt/m is attached to the backside of m2 as shown in the diagram below. When the blocks collide, what is the maximum compression of the spring? Assume that the spring doesn't bend and always obeys Hooke's law.

Homework Equations


I'm not really sure how to do this but:
p=mv
KE=1/2mv^2
KE=1/2kx^2

The Attempt at a Solution


p1=20kgm/s p2=15kgm/s
KE1=100J KE2=22.5J
I have no idea what to do now though, or even if I need any of that information
 
Last edited:
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A kinetic energy cannot have units of Watts.
You could consider the center of mass system - before the collision and at the point of maximal spring compression.
 
mfb's centre of mass approach is good. Alternatively, consider what the relationship is between the velocities when the spring is at maximum compression.
What conservation laws do you know that might be useful?
 

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