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Find dy/dx of x^2 − (y^2) x = (3x − 3)y

  1. Feb 9, 2012 #1

    x^2−(y^2)x = (3x − 3)y

    Using this graph and the equation I need to find two things.

    (a) Formula which gives the slope dy/dx at every point (x, y) on the graph.
    (b) As you can see in the picture, there are two points on the graph which have x-coordinate equal to 1. What are the exact slopes of the tangent lines at those two points?

    I believe I correctly figured out (a) to be y'(x)= (2x-y^2-3y)/(2xy+3x-3)

    However, I am not sure how to use this formula to find two different slopes for one value of x.
  2. jcsd
  3. Feb 9, 2012 #2


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    That looks correct

    You are given the value of x... what else do you need to calculate the slope at a point?
  4. Feb 9, 2012 #3


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    Since "find a derivative" is NOT differential equations, I am moving this to the Calculus section.
  5. Feb 9, 2012 #4
    I understand now. Thank You!
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