Find e/m Ratio: Lab Report Graph Analysis

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To find the e/m ratio from the graph of V against I^2, the gradient of the linear plot represents e/m multiplied by a constant factor derived from the magnetic field and other parameters. The relationship between V and I^2 is established through the equations provided, where B is proportional to I and V is proportional to B^2. By eliminating B using the given equations, the equation V = (e/m) * K * I^2 can be derived, where K encompasses the constants U, R, n, and r. Once the gradient is obtained from the graph, it can be used to calculate the e/m ratio. Understanding these relationships is crucial for accurately completing the lab report analysis.
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Hi all, I'm new to this forum so sorry if this post is a bit scrappy!

Homework Statement



This is part of a lab report I am doing: Plot a graph of V against I^2 and find the e/m ratio from the gradient.

Homework Equations



e/m = 2V/B^2 r^2 where B is magnetic field, r is radius of electron beam

B = U (4/5)^(3/2) nI/R where U is magnetic constant, n is no. of turns per coil, R is radius of Helmholtz coils

The Attempt at a Solution



I'm not sure what exactly to do once I get the gradient!

Many thanks if anyone can help and feel free to ask if I havn't provided enough info :)
 
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Note that B is proportional to I and V is proportional to B2 giving V proportioanl to I2. If you plot V vs. I2, the plot is linear and the slope (gradient) of the line is e/m times the other constants. Simply eliminate B using the two given equations and solve for V and the slope term will be evident i.e. V = e/m*K*I2 where K are the combined constants of U, R, n and r.
 

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