Find eqn of Tangent Line to graph- Implicit Differentiation

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Homework Help Overview

The problem involves finding the equation of the tangent line to the graph defined by the implicit equation xy² + sin(πy) - 2x² = 10 at the point (2, -3). The subject area includes implicit differentiation and calculus concepts related to tangent lines.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster shares an image of their thought process and expresses uncertainty about their calculated slope, particularly due to the presence of the sin(πy) term. Some participants question the accuracy of the slope derived from the original poster's calculations and suggest that there may be errors in the numerator.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's attempts. There is a recognition of potential errors in the calculations, and the original poster is encouraged to clarify their reasoning and continue working through the problem.

Contextual Notes

The original poster indicates that they are seeking clarification on their current position in the problem-solving process and acknowledges that their solution is not yet complete.

opus
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Homework Statement


Find the equation of the tangent line to the graph of the given equation at the indicated point.

##xy^2+sin(πy)-2x^2=10## at point ##(2,-3)##

Homework Equations

The Attempt at a Solution



Please see attached image so you can see my thought process. I think it would make more sense that typing it out.
My solution is ##\frac{7}{-12-π}## But I don't think this is correct. The ##πy## inside the argument of the sin function is throwing me off.
 
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Image.

Let me add that I know this problem isn't finished. Up to my current position is where I'm seeking clarification.
Thanks!
 

Attachments

  • CCDF6133-4C78-4422-B04B-B2949C3563F1.jpeg
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I cannot read your image without further processing. The denominator looks o.k. but the nominator seems to be wrong. Your slope is roughly ##-\frac{1}{2}## whereas the plot looks more like ##\pm 0##.
 
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Hopefully this makes it better. If not I’ll type it all out.
I’ve broken the image up into two pieces but since the steps are labeled, it should be clear in the order they are.
 

Attachments

  • 944865F2-DF19-45C2-838E-DCC816805EEF.jpeg
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  • 849BB5B3-4B35-409B-8FFD-460B7001D3BD.jpeg
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And what is ##8-9##?
 
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That's embarrassing :DD
So we have ##\frac{-1}{-12-π}## and this makes more sense now. So this is the slope of the tangent line at (2,-3) and now I can continue on hopefully without forgetting how to add.
 
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