MHB Find Equation of Ellipse at (1,2) & (1,8), Minor Axis Length 4

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The equation of the ellipse with center at (1,2), a vertex at (1,8), and a minor axis length of 4 is derived as (x-1)²/16 + (y-2)²/36 = 1. The semi-major axis is determined to be 6, while the semi-minor axis is 2. Participants emphasize the importance of showing work when seeking help to facilitate better guidance. Clarifications are made regarding the lengths of the axes to ensure accurate understanding. The discussion highlights the collaborative nature of problem-solving in mathematics.
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Find equation for center at (1,2) and vertex at (1,8) and Minor axis length of 4?
 
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Hello, schooler!

Did you make a sketch?

Find equation of the ellipse with center (1,2),
and vertex at (1,8) and minor axis length of 4.
Code:
          |
          |   *(1,8)
          |   :
          |   :
          |   :6
          |   :
          |   :   2
      * . | . + . . . *
          |   :(1,2)
    - - - + - : - - - - -
          |   :
          |   :
          |   :
          |   *
          |
We have enough information to write the equation.

. . \frac{(x-1)^2}{4} + \frac{(y-2)^2}{36} \;=\;1
 
schooler said:
Find equation for center at (1,2) and vertex at (1,8) and Minor axis length of 4?

Hello, schooler! :D

We do ask that you show what you have tried so our helpers can see where you are stuck and can help get you unstuck. If you simply post a problem with no work shown, we don't really know how to help, other than perhaps give you hints you have already tried which wastes your time and the time of the helper. Most of our helpers are not going to just work the problem for you, because this does not really get you involved in the process and maximize the "learning moment."
 
soroban said:
\frac{(x-1)^2}{4} + \frac{(y-2)^2}{36} \;=\;1
This should be
\[
\frac{(x-1)^2}{16} + \frac{(y-2)^2}{36}=1
\]
 
Hello, Evgeny!

The semi-major axis has length 6.
Hence: a = 6.

The minor axis has length 4.
The semi-minor axis has has length 2.
Hence: b = 2.

 
Sorry, you are right. I read it as the minor semi-axis has length 4.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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