Find Equivalent Inductance for 3 Inductors: 6mH, 8mH, 6mH

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The equivalent inductance for a circuit containing two 6.0 mH inductors in series and one 8.0 mH inductor in parallel is calculated to be 4.8 mH. The series inductance of the two 6.0 mH inductors totals 12.0 mH, which is then combined with the 8.0 mH inductor using the parallel inductance formula. This calculation confirms that the total inductance is 4.8 mH, aligning with established rules for combining inductors, which are analogous to those for resistors.

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A circuit contains two inductors of 6.0 mH inductance in series placed in parallel with an inductor of 8.0 mH inductance. After one of the 6.0 mH inductors burns out, the repair person wants to replace all three inductors with one inductor of equivalent inductance. What inductance should she use?



1. 3.0 mH

2. 4.8 mH

3. 3.4 mH

4. 11 mH

5. 20 mH

Two 6 mH in series = L1+L2 = 6+6= 12mH
this is in parallel with 8mH

so,,total L = 12*8/20 = 4.8mH

Is this correct?
 
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yes, it is correct. The rules for series and parallel inductances are the same as
those for resistances.
 

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