Find Focus of Parabola: y:-(1/4)x^2 + 2x - 5

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SUMMARY

The discussion focuses on finding the focus of the parabola represented by the equation y = -(1/4)x^2 + 2x - 5. The solution involves manipulating the equation by multiplying by 4 to eliminate the fraction and completing the square to derive the standard form. The focus of a parabola is defined mathematically as the point equidistant from a line and a point, and it can be determined from the standard form of the equation, which is (x - x0)^2 = 4a(y - y0), where 'a' represents the distance from the vertex to the focus.

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  • Understanding of quadratic equations and their standard forms
  • Knowledge of completing the square technique
  • Familiarity with the geometric properties of parabolas
  • Basic concepts of polar coordinates and their relation to conic sections
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  • Study the derivation of the standard form of a parabola from its general equation
  • Learn how to convert between Cartesian and polar coordinates for conic sections
  • Explore the properties of parabolas in optics, particularly in relation to parabolic reflectors
  • Practice problems involving the identification of foci and vertices of various parabolas
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Students studying algebra and geometry, educators teaching conic sections, and anyone interested in the mathematical properties of parabolas.

bengaltiger14
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Homework Statement



Find the focus of parabola: y:-(1/4)x^2 + 2x - 5

The Attempt at a Solution



Multiplying by 4 to get rid of fraction I get:
4y:-x^2 + 2x - 5

I will bring over the -5:
4y+5:-x^2 +2x

Completing Square I obtain:

4y+6:-(x-1)^2


Is all this correct thus far?
 
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Do you know what a focus of a parabola is? I think it has something to do with polar coordinates.
 
The focus is the central point of a parabola I believe. It determines if parabola points up or down
 
bengaltiger14 said:
The focus is the central point of a parabola I believe. It determines if parabola points up or down
That is the extreme point of a parabola, not a focus.

A physical definition for focus could be this: If you shine parallel beams of light on the parabolic surface, it all reflects and focuses in a special point, called a focus. (A parabolic telescope).

A mathematical one: every point of a parabola has equal distances to a line and a point. The point is called a focus.

Further, if you write down the equation of parabola in polar coordinates in its simplest form, the pole is the focus of parabola.
 
Irid said:
That is the extreme point of a parabola, not a focus.

A physical definition for focus could be this: If you shine parallel beams of light on the parabolic surface, it all reflects and focuses in a special point, called a focus. (A parabolic telescope).

A mathematical one: every point of a parabola has equal distances to a line and a point. The point is called a focus.

Further, if you write down the equation of parabola in polar coordinates in its simplest form, the pole is the focus of parabola.

All very true. But you don't NEED polar coordinates. If you write a standard form for the parabola in cartesian coordinates x^2=4ay the vertex is at the origin and the distance from vertex to focus is 'a'. You just have to write your quadratic in a form similar to the standard form. Like (x-x0)^2=4a(y-y0). Now you have vertex at (x0,y0) and distance to focus 'a'.
 

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