Find Ground State Energy of 3D Harmonic Oscillator

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SUMMARY

The discussion focuses on finding the exact ground state energy of the Hamiltonian for a 3D harmonic oscillator. Participants suggest rewriting the equation using new variables, specifically defining \(\vec{R} = \frac{1}{2} (\vec{r}_1 + \vec{r}_2)\) and \(\vec{r} = \vec{r}_1 - \vec{r}_2\). This substitution aims to separate the Hamiltonian into two distinct Hamiltonians, one dependent on the \(\vec{R}\) coordinate and the other on the \(\vec{r}\) coordinate. Clarifications regarding typographical errors in the equations were also requested to ensure accurate communication.

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koustav
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Summary:: I am trying to find the exact ground state energy of the hamiltonian.kindly help me with this

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I suggest rewriting your equation in terms of new variables:

##\vec{R} = \frac{1}{2} (\vec{r}_1 + \vec{r}_2)##
##\vec{r} = \vec{r}_1 - \vec{r}_2##
 
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To the OP, would you clarify the typo in the last term, just so we are all certain what we're working with.
 
Haborix said:
To the OP, would you clarify the typo in the last term, just so we are all certain what we're working with.
there will be vector sign and no square on the last term
 
Thank you. Stevendaryl's suggestion is a good one, give it a try and let us know how you get along. The goal of that kind of substitution is to get a Hamiltonian which separates into a sum two Hamiltonians, one in the ##R## coordinate and the other in the ##r## coordinate.
 

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