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## Homework Statement

8.00 g of aluminum at 200 °C and 18.0 g of copper are dropped into 50.0 cm

^{3}of ethyl alcohol at 15 °C. The temperature quickly comes to 26.0 °C. What was the initial temperature of the copper?

Density of ethyl alcohol = .789 g/ml

mass of ethyl alcohol = 39.45 g, .03495 kg

mass of copper = .018 kg

mass of aluminum = .008 kg

T

_{f}= 299 K

T

_{i, alum}= 473 K

T

_{i, eth}= 288 K

c for aluminum = 900 J/kg*k

c for ethyl alcohol = 2400 J/kg*k

c for copper = 385 J/kg*k

## Homework Equations

Q

_{a}+ Q

_{c}+ Q

_{e}= m

_{a}c

_{a}ΔT + m

_{e}c

_{e}ΔT + m

_{c}c

_{c}ΔT = 0

## The Attempt at a Solution

Q

_{a}+ Q

_{c}+ Q

_{e}= m

_{a}c

_{a}ΔT + m

_{e}c

_{e}ΔT + m

_{c}c

_{c}ΔT = 0

=(.008)(900)(-174) + (.03945)(2400)(11) + (.018)(385)(299-Ti) = 0

Ti = 268.51 K or -4.5 °C

That's what I did, but it says not quite and tells to check for rounding errors. However, I didn't round anything until the very end, so I'm not quite sure where I went wrong. I also tried -4.494 but that was wrong too.