What Is the Initial Temperature of Copper in a Mixed Substance System?

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Homework Help Overview

The problem involves determining the initial temperature of copper in a system containing aluminum and ethyl alcohol, with given masses and temperatures. The final temperature of the system is also provided.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the application of the heat transfer equation Q=mcΔT, with attempts to set up an equation balancing heat lost and gained among the substances. Some participants express uncertainty about the correct placement of copper in the heat transfer equation.

Discussion Status

Some guidance has been offered regarding unit conversion and the formulation of the heat transfer equation. Participants are exploring different interpretations of the problem setup and the relationships between the substances involved.

Contextual Notes

There is mention of potential errors in calculations, such as an incorrect initial temperature result for copper. Participants are also considering the implications of specific heat capacities and the need for consistent units.

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Homework Statement



What is the initial temperature of copper if, 11 g aluminum at 200 C and 21 g of copper are dropped into 46 cm^3 of ethyl alcohol at 15 C. The final temperature of the system is 22 C.




Homework Equations



Q=McT

The Attempt at a Solution



My work : Qal+Qcu+Qea=0, and solved for the intial temperature. I got -130 C which was wrong. To find the mass of ethyl alcohol, i used volume and density. Volume is 790 kg/m^3
 
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Try converting everything into the same units (eg kg)
 


i converted everything and got this formula

m1 * s1 * t1 + m2 * s2 * t2 + = m1 * s1 * tf + m2 * s2 * tf + m3 * s3 * tf

m1= aluminum
m2=coppper
m3=ethtyl alcohol,

i just can't get the write answer.
 


In Q=mcT , 'T' is the change in temperature
 


yea, i took that into account, so i did heat loss=heat gained, and the heat lost was by the aluminum, and i know the ethyl alcohol gained heat, but I am not sure what side the copper would go on
 


Al goes from 200 to 22
Cu goes from T to 22
Ethyl goes from 15 to 22

So
m_al * c_al * (200-22) + m_cu * c_cu * ( T-22) + m_eth * c_eth * (15-22) = 0
 

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