Find integrating factor and solve the equation 2

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SUMMARY

The discussion focuses on solving the differential equation (1 - x - z)dx + dz = 0 by finding an integrating factor. The integrating factor calculated is e^((-x^2)/2), derived from the expression 1/N[dM/dz - dN/dx] = 1[-x]. Despite this, the user encountered issues with the equation not being exact. A correction was made regarding the differentiation, revealing that the integrating factor should actually be -1, as pointed out by another user.

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naspek
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Question:

(1 - x - z)dx + dz = 0

let M = (1 - x - z) ; N = 1

dM/dz = -x ; dN/dx = 0
hence, not exact.

integrating factor...

1/N[ dM/dz - dN/dx ] = 1[-x]
.......= -x

e^∫-x dx = e ^ [(-x^2)/2]


times integrating factor with DE..

{e ^ [(-x^2)/2] -x e ^ [(-x^2)/2] - z e ^ [(-x^2)/2]}dx +
e ^ [(-x^2)/2]dz = 0

dM/dz = -e ^ [(-x^2)/2] ; dN/dx = -xe ^ [(-x^2)/2]

the problem is, i calculated the integrating factor.. but, the equations still not the exact calculation.
 
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naspek said:
let M = (1 - x - z)

dM/dz = -x

Did you forget how to differentiate?:wink:
 
gabbagabbahey said:
Did you forget how to differentiate?:wink:

oh s#|t..!
it should be -1
thanks gabbagabbahey
 

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