Find Inverse of A w/ Trig Functions: Step-by-Step Guide

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SUMMARY

The discussion focuses on finding the inverse of a matrix A defined by trigonometric functions, specifically using the matrix A = \(\begin{bmatrix}\cos \phi & -\cos \theta \sin \phi & \sin \theta \sin \phi \\ \sin \phi & \cos \theta \cos \phi & -\sin \theta \cos \phi \\ 0 & \sin \theta & \cos \theta\end{bmatrix}\). The preferred method for calculating the inverse is the transposed cofactor matrix method, although row-reduction can also be applied. It is crucial to ensure that the specified angles \(\theta\) and \(\phi\) do not lead to a non-invertible matrix.

PREREQUISITES
  • Understanding of matrix operations, specifically matrix inversion
  • Familiarity with trigonometric functions and their properties
  • Knowledge of the transposed cofactor matrix method for finding inverses
  • Basic concepts of linear algebra, including row-reduction techniques
NEXT STEPS
  • Study the transposed cofactor matrix method in detail
  • Learn about conditions for matrix invertibility and how trigonometric functions affect them
  • Explore row-reduction techniques for matrix inversion
  • Investigate applications of trigonometric matrices in various fields such as physics and engineering
USEFUL FOR

Mathematicians, students studying linear algebra, and professionals working with trigonometric matrices in engineering or physics will benefit from this discussion.

Reshma
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Find the inverse of A given by:
[tex]A = \left[\begin{array}{ccc}\cos \phi & -\cos \theta \sin \phi & \sin \theta \sin \phi \\\sin \phi & \cos \theta \cos \phi & -\sin \theta \cos \phi \\0 & \sin \theta & \cos \theta\end{array}\right][/tex]

I have never encountered a problem in Matrices involving long trigonometric functions. How do I find the inverse? Should I use the same row-reduction method for this?
 
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Use whatever method you prefer (I like the transposed cofactor matrix method, personally). Once you specify [itex]\theta, \ \phi[/itex], they're just numbers (you should, of course, check to make sure that there are no values of these that stop the matrix from being invertible!).
 
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Ok, thanks a lot! I will try it out.
 

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