Find Inverse of y=(x)^(1/3) & y=3(2)^x

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Homework Help Overview

The discussion revolves around finding the inverses of the functions y=(x)^(1/3) and y=3(2)^x. Participants are exploring the methods for determining these inverses, noting that the formulas are not found in their textbooks.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of interchanging x and y as a starting point for finding inverses. There are questions about the algebraic rules necessary for these transformations, and some participants express uncertainty about their understanding of these rules.

Discussion Status

Some guidance has been provided regarding the process of interchanging variables and solving for y. However, there is a mix of understanding among participants, with some expressing confidence in the method while others question their algebraic skills.

Contextual Notes

There are indications of missing information regarding algebraic rules, and one participant mentions difficulty with using LaTeX for equations. This suggests a potential barrier to clear communication of mathematical expressions.

thomasrules
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yea ok but wait how do u find the inverse of like

y=(x)^(1/3)

y=3(2)^x

whats the formula is not in the book

BTW i can't do those equations in latex...
 
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interchange x and y, and solve for y.
 
answer says y=x^3
 
which is exactly what courtrigrad's method predicts:

1° interchange x and y: y=(x)^(1/3) --> x=y^(1/3)

2° solve for y: x=y^(1/3) --> y=x^3
 
make sure you understand algebra thomas, if you don't know all the algebra rules now, learn them b4 it's too late!
 
For y= 3(2x), again do what courtrigrad said: Swap x and y to get x= 3(2y) and solve for y by taking logs of both sides:
log(x)= log(3(2y))= ylog(2)+ log(3)
y log(2)= log(x)- log(3)= log(x/3)
y= log(x/3)/log(2).
 

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