Find 'k' for x(t)=k is solution for diff eq

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SUMMARY

The discussion focuses on finding the constant value of k for which the function x(t) = k is a solution to the differential equation 6t^5 dx/dt + 7x - 4 = 0. The correct approach involves recognizing that since x(t) = k, the derivative x'(t) = 0. Substituting these values into the equation simplifies to 7k - 4 = 0, leading to the conclusion that k = 4/7. This method emphasizes the importance of correctly identifying constant functions in differential equations.

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Homework Statement



Find the value of k for which the constant function x(t)=k is a solution of the differential equation 6t^5dx/dt+7x−4=0.

The Attempt at a Solution



I have tried this several ways but no luck, here is one of my attempts,

solve for dx/dt,

dx/dt = (4-7x)/6t^5

take the integral,

x(t) = (1/6t^5)(4x-7x^2/2)

and that doesn't help :P
I am sure as usual I am missing something straightforward but I don't see it.
 
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You have ##x(t) = k## therefore ##x'(t) = 0##.

Plugging those in yields :

##(6t^5)(0) + 7k − 4= 0##

I'm sure that you got this now. It's the same concept as in your prior thread.
 
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Zondrina said:
You have ##x(t) = k## therefore ##x'(t) = 0##.

Plugging those in yields :

##(6t^5)(0) + 7k − 4= 0##

I'm sure that you got this now. It's the same concept as in your prior thread.

You know...
At least missing these types of things typically only happens once.

Thanks again!
 

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