Find Limit of $\frac{n^3}{(n + 1)^2}$ as $n$ Approaches ∞

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SUMMARY

The limit of the expression $\frac{n^3}{(n + 1)^2}$ as $n$ approaches infinity simplifies to $\frac{n}{(1 + \frac{1}{n})^2}$. This transformation is achieved by factoring out $n^2$ from the denominator, allowing for the limit to be evaluated more easily. As $n$ approaches infinity, the term $(1 + \frac{1}{n})^2$ approaches 1, leading to a final limit of 1. The discussion emphasizes the importance of algebraic manipulation in limit evaluation.

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I need to find the limit of

$$\left| \frac{(n + 1)n^3}{(n + 1)^{3}} \right|$$

as $n$ approaches infinity.

I simplify this to:

$$\left| \frac{n^3}{(n + 1)^{2}} \right|$$

But the solution simplifies it to:

$$\left| \frac{n}{(1 + \frac{1}{n})^{2}} \right|$$

How do I get to this result?
 
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tmt said:
I need to find the limit of

$$\left| \frac{(n + 1)n^3}{(n + 1)^{3}} \right|$$

as $n$ approaches infinity.

I simplify this to:

$$\left| \frac{n^3}{(n + 1)^{2}} \right|$$

But the solution simplifies it to:

$$\left| \frac{n}{(1 + \frac{1}{n})^{2}} \right|$$

How do I get to this result?
[math]\left | \frac{n^3}{(n + 1)^{2}} \right |[/math]

[math]= \left | \frac{n^2 \cdot n}{(n + 1)^{2}} \right | = \left | \frac{n}{\frac{(n + 1)^{2}}{n^2}} \right |[/math]

Can you finish from here?

-Dan
 

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