Find linear dependence on these vectors

Click For Summary
SUMMARY

The discussion focuses on finding linear dependence among the vectors in the set X = {(1,0,-2,1),(2,-2,0,3),(0,2,-4,-1),(-1,2,-2,-2)} within the vector space V = R^4. The user successfully reduced the matrix formed by these vectors to echelon form, revealing two non-zero rows and two null rows. This indicates that the vectors are linearly dependent, allowing for the extraction of a smaller generating set for U. The user seeks clarification on deriving a specific linear combination from the echelon form equations.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically linear dependence and basis.
  • Proficiency in matrix operations, including row echelon form (REF) and reduced row echelon form (RREF).
  • Familiarity with vector spaces, particularly R^4.
  • Knowledge of solving systems of linear equations.
NEXT STEPS
  • Study the process of finding a basis for a vector space using linear combinations.
  • Learn about the implications of null rows in echelon form regarding linear dependence.
  • Explore techniques for expressing one vector as a linear combination of others.
  • Review examples of generating sets and bases in higher-dimensional vector spaces.
USEFUL FOR

Students of linear algebra, educators teaching vector spaces, and anyone involved in mathematical problem-solving related to linear dependence and basis formation.

ashina14
Messages
32
Reaction score
0

Homework Statement


Suppose V = R^4 and let U = <X>, where X = {(1,0,-2,1),(2,-2,0,3),(0,2,-4,-1),(-1,2,-2,-2)}
Find linear dependence on X and use it to find a smaller generating set of U. Repeat the step until you reach a basis for U.


Homework Equations





The Attempt at a Solution



I have formed a matrix of the 4 vectors in X and reduced it to echelon form. I got
(1 | 0 | 2 | 1
0 | 1 | -1 | -1
0 | 0 | 0 | 0
0 | 0 | 0 | 0)

Let's say the 4 vectors were s, t, u, v respectively.
Then xs + xt + yu + zv = 0 is true for some constants w,x,y,z (1)

Then according to the REF form we can form two equations: w = 2y +z and x = -y+z
I thought I could substitute these into equation (1) and end up showing one vector as a combination of the others but I am not able to reach anywhere. Where am I wrong? Is there a better method to go about this?
 
Physics news on Phys.org
I would have thought that the relationship was implied by the steps to get the echelon form. I.e. in producing the null rows, you effectively executed the equation you're looking for.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
12
Views
2K
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
2
Views
2K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K