Find Magnetic Field Using Torque Equation (t=nBIAcos)

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SUMMARY

The discussion centers on manipulating the torque equation \( T = nBIA \cos \theta \) to isolate the magnetic field \( B \). Participants confirm that rearranging the equation is feasible by dividing both sides by \( nIA \cos \theta \), leading to the formula \( B = \frac{T}{nIA \cos \theta} \). This approach clarifies how to derive the magnetic field from given torque, number of turns, current, area, and angle.

PREREQUISITES
  • Understanding of torque equations in physics
  • Familiarity with magnetic fields and their properties
  • Basic algebraic manipulation skills
  • Knowledge of the variables involved: torque (T), number of turns (n), current (I), area (A), and angle (θ)
NEXT STEPS
  • Study the derivation of the torque equation in electromagnetism
  • Learn about the relationship between torque and magnetic fields in motors
  • Explore practical applications of the torque equation in engineering
  • Investigate the effects of varying each parameter on the magnetic field strength
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in understanding the relationship between torque and magnetic fields in practical applications.

centripitacal
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This is really just a matter of curiosity. Can you manipulate the torque equation of (t=nBIAcos) to find the magnetic field, B?

Or do you just stick to the other formulas?
 
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Assuming you are given the torque,n,I,A and θ. Then of course you can rearrange it. (Is that the equation for torque? I can't remember it properly)
 
Yes, that's the equation for torque. How could you rearange it to B (the magnet field). I am having trouble with equations like this one , with more than three factors. How would you rearange this one?
 
centripitacal said:
Yes, that's the equation for torque. How could you rearange it to B (the magnet field). I am having trouble with equations like this one , with more than three factors. How would you rearange this one?

Think of the equation like this

T=nBIAcosθ

T= B (nIAcosθ)

and you can divide both sides by 'nIAcosθ'
 
Gracias, thank you for your help.
 

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