Find Magnetic Field Using Torque Equation (t=nBIAcos)

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Homework Help Overview

The discussion revolves around manipulating the torque equation \( t = nBIA \cos \theta \) to isolate the magnetic field \( B \). Participants are exploring the relationships between the variables involved in this equation.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Some participants question how to rearrange the torque equation to solve for \( B \). There are discussions about the validity of the equation and the challenges of manipulating equations with multiple factors.

Discussion Status

Participants are actively engaging with the equation and attempting to clarify their understanding of how to isolate \( B \). Some guidance has been provided on rearranging the equation, but no consensus has been reached on the best approach.

Contextual Notes

There is uncertainty regarding the manipulation of the equation, and some participants express difficulty with equations that involve multiple variables. The context suggests that the discussion is framed within a homework help scenario, where assumptions about given values are being considered.

centripitacal
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This is really just a matter of curiosity. Can you manipulate the torque equation of (t=nBIAcos) to find the magnetic field, B?

Or do you just stick to the other formulas?
 
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Assuming you are given the torque,n,I,A and θ. Then of course you can rearrange it. (Is that the equation for torque? I can't remember it properly)
 
Yes, that's the equation for torque. How could you rearange it to B (the magnet field). I am having trouble with equations like this one , with more than three factors. How would you rearange this one?
 
centripitacal said:
Yes, that's the equation for torque. How could you rearange it to B (the magnet field). I am having trouble with equations like this one , with more than three factors. How would you rearange this one?

Think of the equation like this

T=nBIAcosθ

T= B (nIAcosθ)

and you can divide both sides by 'nIAcosθ'
 
Gracias, thank you for your help.
 

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