Find Magnitude of Vectors AB and BC in 2D Space | Vector Addition"

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Homework Help Overview

The problem involves finding the magnitude of the vector sum of two vectors, \(\vec{AB}\) and \(\vec{BC}\), derived from three points in 2D space: A (-3,7), B (5,22), and C (8,18). Participants are exploring the relationship between the vectors and their magnitudes.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Some participants discuss whether the magnitude of the sum of two vectors is equal to the sum of their magnitudes, questioning the validity of this assumption.
  • Others suggest that \(|\vec{AB} + \vec{BC}| = |\vec{AC}|\) and express confusion about the necessity of using the cosine law as suggested by the teacher.
  • There are attempts to clarify the relationship between the vectors and their geometric interpretation.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the vector relationships. Some have provided insights into the geometric meaning of the vectors, while others remain uncertain about the application of the cosine law. No consensus has been reached regarding the necessity of the cosine law in this context.

Contextual Notes

Participants are grappling with the implications of their teacher's insistence on using the cosine law, which has led to questions about the assumptions underlying the problem setup. There is also mention of potential confusion regarding the correct interpretation of the vectors involved.

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Homework Statement



Given:
A (-3,7)
B (5,22)
C (8,18)
are 3 points in 2D space.

Find |\vec{AB} + \vec{BC}|[/tex]<br /> <br /> <h2>Homework Equations</h2><br /> ||\vec{v} - \vec{w}||^2 = ||\vec{v}||^2 + ||\vec{w}||^2 - 2 ||\vec{v}|| \cdot ||\vec{w}|| \cos \theta<br /> <br /> <br /> <h2>The Attempt at a Solution</h2><br /> Isn&#039;t |\vec{AB} + \vec{BC}|[/tex] just |\vec{AB}| + |\vec{BC}|[/tex]? I mean, isn&amp;amp;#039;t the magnitude of the sum of 2 vectors the same as adding the 2 magnitudes together?
 
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Draw it out and see :smile:
 
I tried. What I'm confused about is the interpretation of |\vec{AB} + \vec{BC}|[/tex]<br /> <br /> I mean, mathematically, I believe I can do this:<br /> |\vec{AB} + \vec{BC}|[/tex] = |\vec{AC}|[/tex]&amp;lt;br /&amp;gt; Because \vec{AB} + \vec{BC}[/tex] = \vec{AC}[/tex]&amp;amp;amp;lt;br /&amp;amp;amp;gt; &amp;amp;amp;lt;br /&amp;amp;amp;gt; In which case, |\vec{AB} + \vec{BC}|[/tex] is intuitive.&amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;gt; But I might be getting myself confused&amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;gt; &amp;amp;amp;amp;lt;br /&amp;amp;amp;amp;gt; Lastly, my teacher insisted that the cosine law be used, and I have no idea why.
 
Edit: Disregard this post
 
Last edited:
So are you saying |\vec{AB} + \vec{BC}|[/tex] = |\vec{AC}|[/tex]?&lt;br /&gt; &lt;br /&gt; If so, why does my teacher insist that I use the cosine law?
 
hahutzy said:
So are you saying |\vec{AB} + \vec{BC}|[/tex] = |\vec{AC}|[/tex]?
&lt;br /&gt; &lt;br /&gt; Oh wait wait, my bad, I didn&amp;#039;t read those vectors correctly. Disregard my first post.&lt;br /&gt; &lt;br /&gt; Yes, the magnitude of (AB + BC) is equal to the magnitude of AC because the vector AC is the same as the vector you get from adding AB and BC thus it has the same magnitude.
 
I still don't understand why I would need to use cosine law for this, as claimed by my teacher...
 
Unless I'm not seeing something, I don't see the need for it. Are you sure you aren't looking for |AC + BC|?
 
hahutzy said:
|\vec{AB} + \vec{BC}|[/tex] just |\vec{AB}| + |\vec{BC}|[/tex]
&lt;br /&gt; &lt;br /&gt; No but ]|\vec{AB} + \vec{BC}|[/tex] and |\vec{AB}| + |\vec{BC}|[/tex] are related. Question: how?
 
  • #10
<br /> \vec{AB} + \vec{BC}= \vec{CA}<br />

So, you need to find |\vec{-AC}|=|\vec{AC}|

Regards.
 

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