fiksx
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i just wanted to show that ##x=\beta## ,ehild said:That is wrong. can be β2 negative?
##\alpha^2+\beta^2=4## and α=1, what is β2?But what values can β have?No, how come that ##1+x^2=\sqrt 3## ? This must be ##\vec c \cdot \vec c ## which is 4.
Can not have β some other value?
If β2=3 β can be √3 or -√3, but √3 is positive. At the end you wrote the correct solution, but take more care to the derivations.
anyway what i learn from this problem is from a.b=0, dot product=0 show that a and b is orthogonal to each other. so it imply a and b is independent to each other and it span the plane(?) while c is dependent to both a and b, it is in the span of a and b?
but without finding c coordinate, how can you know the angle between b and c can be 150 degree?