Find Orig. Speed 3.0kg Mass After Frictionless Explosion

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SUMMARY

The original speed of a 3.0 kg mass sliding on a frictionless surface, which explodes into three 1.0 kg masses, can be determined using the principle of conservation of momentum. The final velocities of the masses are 9.0 m/s north, 4.0 m/s at 30 degrees south of west, and 4.0 m/s south of east. By applying vector addition to the momentum equations, the original speed can be calculated as 6.0 m/s in the direction opposite to the resultant momentum vector of the three smaller masses.

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Homework Statement


A 3.0 kg mass sliding on a frictionless surface explodes into 3 1.0kg masses. After the explosion the velocities of the three masses are: (1) 9.0 m/s north, (2) 4.0 m/s 30 degrees south of west, and (3) 4.0 m/s south of east. What is the original spped of the 3.0 kg mass?


Homework Equations



Pi=Pf
P=mv

The Attempt at a Solution


Pi=Pf
3v= (1)9+ (1)4+(1)4
I know this is wrong. I am confused about what to use for the magnitude and direction of these velocities. would it be 4tan(3) for both of them?
 
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ScullyX51 said:
A 3.0 kg mass sliding on a frictionless surface explodes into 3 1.0kg masses. After the explosion the velocities of the three masses are: (1) 9.0 m/s north, (2) 4.0 m/s 30 degrees south of west, and (3) 4.0 m/s south of east. What is the original spped of the 3.0 kg mass?

Pi=Pf
3v= (1)9+ (1)4+(1)4
I know this is wrong. I am confused about what to use for the magnitude and direction of these velocities. would it be 4tan(3) for both of them?

Hi ScullyX51! :smile:

Momentum is a vector, so you must use vector addition, not ordinary addition.

(since there are four vectors, a vector triangle won't be very much use :rolleyes:, so: ) use x and y coordinates. :smile:
 

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