# Find parametric eq for a line with point and plane

marquitos
Find parametric equations for the line through Po=(3,-1,1) perpendicular to the plane 3x+5y-7z=29.

Hey guys im slightly confused on where to even start on this one the only way i can think about doing it would be finding two other coordinates on the and then taking the cross product of the two vectors but honestly im not really sure how to obtain the other two points either. So any help would be nice i might just be over thinking it. Thank you.

dangish
well i would go,

|x|...|3| ...|3|
|y|= |-1|+t|5|
|z|...|-1| ..|-7|

then you have x = 3+3t , y= -1+5t, and z = -1-7t

is this of any help?

Last edited:
Homework Helper
Gold Member
Find parametric equations for the line through Po=(3,-1,1) perpendicular to the plane 3x+5y-7z=29.

Hey guys im slightly confused on where to even start on this one the only way i can think about doing it would be finding two other coordinates on the and then taking the cross product of the two vectors but honestly im not really sure how to obtain the other two points either. So any help would be nice i might just be over thinking it. Thank you.

Remember that the normal to the plane (which is obvous, no?) will do for a direction vector for the line.