Find parametric equations and symmetric equations for the line

Click For Summary
SUMMARY

The discussion focuses on deriving parametric and symmetric equations for a line through the point P0 = (1, 1, 0) that is perpendicular to the vectors i + j and j + k. The symmetric equations are established as (x - 1)/1 = (y - 1)/(-1) = (z - 0)/1, resulting from the cross product of the two vectors, yielding the direction vector <1, -1, 1>. To find the parametric equations, one should set each fraction in the symmetric form equal to a parameter t and solve for x, y, and z accordingly.

PREREQUISITES
  • Understanding of vector operations, specifically cross products.
  • Familiarity with parametric equations and symmetric equations of lines in three-dimensional space.
  • Knowledge of how to manipulate equations to isolate variables.
  • Basic comprehension of coordinate geometry in 3D.
NEXT STEPS
  • Study vector cross product operations in detail.
  • Learn how to derive parametric equations from symmetric equations.
  • Explore applications of lines in three-dimensional geometry.
  • Practice problems involving lines defined by points and direction vectors.
USEFUL FOR

Students studying multivariable calculus, geometry enthusiasts, and anyone seeking to understand the relationship between parametric and symmetric equations of lines in three-dimensional space.

sonutulsiani
Messages
136
Reaction score
0

Homework Statement



Find parametric equations and symmetric equations for the line through P0 and perpendicular to both given vectors. (P0 corresponds to t = 0.)
P0 = (1, 1, 0)
i + j and j + k

Homework Equations





The Attempt at a Solution




For the symmetric equations, I did this:

(i + j) x (j + k) = k - j + i = <1,-1,1>.

So, the symmetric equations are given by
(x - 1)/1 = (y - 1)/(-1) = (z - 0)/1.

I don't know how to find parametric equation.
 
Physics news on Phys.org
Is it 1+t, 1-t and t?
 
Just set each fraction in your symmetric form equal to t and solve for x, y, and z, respectively. You should have x, y, and z in your equations with t.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K