Find plane's acceleration from mass on a string

Click For Summary

Homework Help Overview

The problem involves a pendulum in a jet plane that accelerates uniformly, affecting the pendulum's equilibrium position. The subject area relates to dynamics and forces, particularly in non-inertial reference frames.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the angle based on the pendulum's displacement and question the correctness of the original poster's approach. Some suggest considering fictitious forces and applying Newton's second law in both horizontal and vertical directions.

Discussion Status

The discussion includes attempts to clarify the original poster's calculations and reasoning. Some participants provide insights into the implications of the results, indicating that the original calculation may not be valid. The original poster expresses uncertainty about the angle calculation but later indicates a resolution.

Contextual Notes

There is a mention of the need to consider forces in a non-inertial frame and the implications of the pendulum's angle in relation to the plane's acceleration. The original poster's calculations and assumptions are under scrutiny.

psal
Messages
4
Reaction score
0

Homework Statement


A pendulum has a length L = 1.13m. It hangs straight down in a jet plane about to take off as shown by the dotted line in the figure. The jet then accelerates uniformly, and while the plane is accelerating, the equilibrium position of the pendulum shifts to the position shown by the solid line, with D = 0.370m. Calculate the magnitude of the plane's acceleration.

prob48_sidepend.gif


Homework Equations


Lsinθ = D
a = gsinθ

The Attempt at a Solution


sinθ = 0.37/1.13
θ = 19.11 deg
9.8sin(19.11) = 3.209

I thought that is the correct way to solve it, but I am not getting the correct answer, and I cannot think of another way to go about it.
 
Last edited:
Physics news on Phys.org
I think it is called fictitous force.
You assume there is a force pulling it to the right.
 
Or write Newton's second law for horizontal and vertical directions.

By the way, one can tell that you result is not right without going through the calculations. If it were, you will have a horizontal string (angle=90 degrees) when a=g. There will be no tension component to balance the weight.
 
Okay, did I at least calculate the angle correctly?

Edit: Figured it out. Thanks for the help.
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 5 ·
Replies
5
Views
6K
Replies
4
Views
6K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
16
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K