Find Pressure amplitude from given decibels

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SUMMARY

The discussion centers on calculating the pressure amplitude from a given sound intensity level of 49 dB. The relevant equations used are β=10log(I/I0) and I≈P^2, with Po set at 2x10^-5. The correct pressure amplitude calculated is 0.0056 Pa, which aligns with the significant figures derived from the intensity level. The user faced issues with online homework systems misinterpreting the answer due to formatting discrepancies.

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Angie_Agnes
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Homework Statement


A sound wave has an intensity level of 49 dB. What is the pressure amplitude of this wave?

Po= 2x10^-5

Homework Equations



β=10log(I/I0)
I≈P^2

The Attempt at a Solution


I can't figure out why I'm getting this problem wrong. So I set it up, 49=10log(I/I0)
-> 4.9=log(I/I0) -> 10^4.9=(I/I0) From there, I replaced the intensity for pressure amp (equation 2) -> p=(2*10^-5)√(10^4.9)
Pamp=.0056Pa

??
 
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Hi Angie_Agnes! :smile:

You calculation looks good.
Any reason to doubt your result?
 
yes, it's online homework and says it's wrong :(
 
Well, I think you have to tweak your result a bit then.
I believe it is numerically correct, but these online homework sites can be a bit difficult with the exact phrasing.
Btw, I'm assuming you did not make a typo in the problem statement...
 
I copied and pasted the question, so no typo... I typed it in as .005 Pa and .006Pa and both came up wrong. Frustrating!
 
With 2 significant digits in 49 dB, it should be 0.0056 Pa or 5.6 mPa.
I can't make anything else from it.
 
THANK YOU! got it right as .0056Pa. Awesome!
 
Huh? But that is your original answer from your opening post! :confused:
 
I looked back at my past answers, I had entered it .005 and .006 at first, before entering it finally as .0056.
 
  • #10
All is well that ends well! :wink:
 

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