1. The problem statement, all variables and given/known data Determine the pressure of the water in pipe A shown in the figure (p2.56) if the gage pressure of the air in the tank is 2 psi. I have attached the image 2. Relevant equations 3. The attempt at a solution Figure P2.56 I drew a jumpline at 2ft above point A because everything below point A has the same density. From here I assigned P1 to account for the pressure above the jumpline in the tank and p2 to account for the pressure in the pipe adjacent to it. P1 = P + ρH2O*3ft P2 = P1 + ρH2O* 4 ft PA = P2 + ρSG*4ft PA = ρSG*4ft + ρH2O*4ft + P + ρH2O*3ft γH2O = 62.4 lb/ft3 taken from textbook SG = ρfluid/ρH2O@4° ρSG = 0.9*1.940 slug/ft3 PA = 4ft(.9*1.940 slugs/ft3) + 62.4 lb/ft3 + 2lb/in[SUP2[/SUP]*144in2/1ft2 + 62.4lb/ft3*3ft PA = 731.784 lb/ft2 My answer should be 525 lb/ft2 I'm not sure where I've gone wrong. I realize that I have slugs in my calculation witht he pressure of the fluid with the given SG but I'm not sure how to deal with them. Any suggestions would be appreciated.