Find System of 2 Equations in 2 Vars for x=t, y=3t-4

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Homework Help Overview

The problem involves finding a system of two equations in two variables, x and y, that corresponds to the parametric equations x=t and y=3t-4, where t is any real number.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of the solution set, questioning whether two equations are necessary given the parametric form. There is mention of deriving one equation, y=3x-4, but uncertainty about obtaining a second equation arises. Some participants suggest that a second equation could be trivial or redundant.

Discussion Status

The discussion is exploring the implications of the problem's requirements. Some participants express doubts about the necessity of two independent equations and consider the possibility of the problem being flawed. There is a recognition that the derived equation does not meet the original question's criteria for a system.

Contextual Notes

Participants note the potential misunderstanding regarding the nature of solutions for systems of equations, particularly in relation to parametric representations and the implications of having multiple equations.

bbdynamite
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Homework Statement


Find a system of two equations in two variables, x and y, that has the solution set given by the parametric representation x=t and y=3t-4, where t is any real number.


Homework Equations


x=t and y=3t-4, where t is any real number


The Attempt at a Solution


y=3x-4 which means that x=(y+4)*1/3. But that is still only one equation and I can't figure out what the other one is. If there are two equations with two unknowns, couldn't the solutions be precise numbers? Since the solution given is parametric, I think there is only one equation in two variables. However, this does not satisfy the question's requirements. What is going on?
 
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bbdynamite said:

Homework Statement


Find a system of two equations in two variables, x and y, that has the solution set given by the parametric representation x=t and y=3t-4, where t is any real number.

Homework Equations


x=t and y=3t-4, where t is any real number

The Attempt at a Solution


y=3x-4 which means that x=(y+4)*1/3. But that is still only one equation and I can't figure out what the other one is. If there are two equations with two unknowns, couldn't the solutions be precise numbers? Since the solution given is parametric, I think there is only one equation in two variables. However, this does not satisfy the question's requirements. What is going on?

I agree with you. It's probably just a mistake in the problem. If you want a second equation you could always suggest something like x=x or something else redundant. But that's pretty pointless.
 
OK thanks for confirming my thought.
 
Two independent equations in x and y will necessarily have a unique solution, not an infinite set of equations as you are given. Yes, x and y must satisfy y= 3x- 4 which I would write as 3x- y= 4. A second equation must be a multiple of that, say, 9x- 3y= 12.
 

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