Find the 50th derivative of the function

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SUMMARY

The discussion focuses on finding the 50th derivative of the function y = sin(3x). Participants outline a pattern in the derivatives, noting that the first derivative is 3cos(3x), the second is -9sin(3x), and so forth. The established rule indicates that for even derivatives, the result is (-1)^(n/2) * (3^n) * cos(3x), while for odd derivatives, it is (-1)^((n-1)/2) * (3^n) * sin(3x). This pattern allows for the efficient calculation of high-order derivatives without direct computation.

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  • Understanding of basic calculus concepts, specifically differentiation.
  • Familiarity with trigonometric functions and their derivatives.
  • Knowledge of the chain rule in differentiation.
  • Ability to recognize and apply patterns in mathematical sequences.
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  • Study the differentiation of trigonometric functions in depth.
  • Explore the concept of higher-order derivatives and their applications.
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  • Investigate the use of mathematical induction to prove derivative patterns.
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Students in calculus, mathematics educators, and anyone interested in advanced differentiation techniques will benefit from this discussion.

Mathysics
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Homework Statement


Find the first, second, third, fourth, fifth derivatives of the function y = sin 3x.

Find a rule that can help to find the 50th derivative of the function.

It's urgent!

Homework Equations


y= sin x y= cos x
y' = cos x y' = -sin x

y= sin ax y= cos ax
y' = a sin cos ax y' = -a sin ax


The Attempt at a Solution


My attempt to the question: y = -a^n sin ax for even
y = a^n cos ax for odd

Plz show steps so that i can follow, cheers
 
Last edited:
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sorry it should be the 50th derivative
 


Mathysics said:

Homework Statement


Find the first, second, third, fourth, fifth derivatives of the function y = sin 3x.

Find a rule that can help to find the 50th derivative of the function.

It's urgent!

Homework Equations


y= sin x y= cos x
y' = cos x y' = -sin x

y= sin ax y= cos ax
y' = a sin cos ax y' = -a sin ax


The Attempt at a Solution


My attempt to the question: y = -a^n sin ax for even
y = a^n cos ax for odd

Plz show steps so that i can follow, cheers
this to me is like a "puzle"; like the problem "find i^15" you find a pattern w/o having to go the whole way. Same here.

So you see the FIRST diff is pos and has the coeff of 3^1 and has "cos" in it
The SECOND diff is neg, coeff is 3^2 and has "sin" in it
The THIRD is neg, coeff is 3^3 and has "cos" in it
The FOURTH is pos, coeff is 3^4 and has "sin" in it..... ummmmm, can you see what the FORTY EIGHTH is now? then so easy to go to the 49th and 50th from there.

Trying hard NOT to give you the ANSWER... AND... apologies if my differentiation is wrong... I'm giving you a pattern to go by... I think diff of sin3x is 3cos3x and then diff of cos3s is -3sin3x? if wrong, FIX that part... I'm trying to show you a PATTERN.

Good luck,

LarryR : )
 


i know it now...

is (-1)^n/2 x a^n cos ax (for even)

thx for the help :)
 

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