Find the accleration of gravity on planet Zircon.

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SUMMARY

The acceleration due to gravity on planet Zircon is calculated to be 1.58 m/s² based on the horizontal toss of a rock at 6.95 m/s. The rock falls a vertical distance of 1.10 meters while traveling a horizontal distance of 8.85 meters. The time of flight was determined to be 1.778 seconds using the equation T = 2ΔX / (Vi + Vf). The calculations confirm that the horizontal component of velocity remains constant, as there is no change in horizontal velocity during the rock's flight.

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zeromodz
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Homework Statement


An astronaut on the planet Zircon tosses a rock horizontally with a speed of 6.95 m/s . The rock falls through a vertical distance of 1.10 meters and lands a horizontal distance of 8.85 meters from the astronaut.


Homework Equations





The Attempt at a Solution



ΔX = 1/2(Vi + Vf)T
T = 2ΔX / (Vi + Vf)
T = (2)(8.85) / (9.95 + 0)
T = 1.778 s


ΔY = ViT + 1/2AT^2
ΔY - ViT = 1/2AT^2
A = 2(ΔY - ViT) / T^2
A = 2(1.10 - 0) / (1.778)^2
A = 1.58 m/s^2
 
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zeromodz said:

The Attempt at a Solution



ΔX = 1/2(Vi + Vf)T
T = 2ΔX / (Vi + Vf)
T = (2)(8.85) / (9.95 + 0)
T = 1.778 s

Where did you get these numbers 8.85 and 9.95?
Why should the horizontal component of the velocity on planet Zircon change?
 

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