1. The problem statement, all variables and given/known data You are given a length of rope, tape and five rocks. The rocks must be attached in such a manner that when the rope is released, the sound of each rock hitting the ground is evenly spaced. There must be a rock at the very bottom and the very top of the rope. When the rope is released, the bottom rock will be just above the ground. A stopwatch cannot be used (time cannot be recorded). 2. Relevant equations Any of the following kinematics equations: d=1/2(Vf+Vi)t Vf=Vi+at d=Vit+1/2at^2 d=Vft-1/2at^2 Vf^2=Vi^2+2ad 3. The attempt at a solution a.) I understand that the rope will accelerate downwards due to gravity. This means that the rock at the top of the rope will have a faster final velocity just before impact than the rock at the bottom of the rope. b.) Assuming that the bottom rock takes 0.1s to hit the ground I made the following calculations: (Trying to space the sounds 0.2 second apart): 2nd rock from the bottom: d = Vit+1/2at^2 d = (0)t + 1/2(9.81m/s^2)(0.3s)^2 d = 0.44 m This means the second rock will be placed 0.44 m from the first rock (0.44 m from the bottom of the rope). 3rd rock from the bottom: d = Vit+1/2at^2 d = (0)t + 1/2(9.81m/s^2)(0.5s)^2 d = 1.23 m This means that the third rock will be placed 1.23 m from the bottom of the rope. Is this the correct approach?