tehmatriks
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Homework Statement
The scale on a map is 1:25000. The length of a wall on the map is 3.2 mm. Find the actual length in metres.
The problem involves determining the actual length of a wall based on a map scale of 1:25000, with the wall's length on the map given as 3.2 mm. Participants are discussing the conversion from map measurements to real-world distances.
The discussion is ongoing, with participants providing corrections and clarifications regarding the calculations. There is acknowledgment of errors in previous posts, and some guidance is offered on how to approach the problem correctly.
Participants note discrepancies in the conversion factors used, particularly regarding the relationship between mm and meters. There is a focus on ensuring that the calculations align with the scale provided in the problem statement.
Mark44 said:Each 1 mm distance on the map represents 25,000 mm (= 2.5 meters) on the ground. If the length of some feature on the map happened to be 10 mm, you would set up a proportion like this, where x represents the actual length of the feature, in mm.
\frac{1}{25000}=\frac{10}{x}
After solving for x in this equation, convert to meters.
Either a typo or a brain fart, 25mMark44 said:25,000 mm (= 2.5 meters)
It shouldn't be cm.tehmatriks said:25,000 x 3.2 = 80,000 x 10-3 = 80 cm
Unfortunately, the latter. It looked odd to me, but I still didn't catch it.Mentallic said:Either a typo or a brain fart, 25m![]()
Mentallic said:It shouldn't be cm.
25,000 x 3.2 mm = 80,000 mm = 80,000 x 10-3 m = 80 m