Mapping Circle to Ellipse with Dilation?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
Stefk

Homework Statement



The problem comes from S. Lang's "Basic mathematics", chapter 7, §1:

"Consider the following generalization of a dilation. Let ##a > 0, b > 0##. To each point ##(x, y)## of the plane, associate the point ##(ax, by)##. Thus we stretch the x-coordinate by ##a## and the y-coordinate by ##b##. This association is a mapping which we may denote by ##F_{a,b}##.

Show that the set of points ##(u, v)## satisfying the equation $$\left( \frac u a \right)^2 + \left( \frac v b \right)^2 = 1$$ is the image of the circle of radius 1 centered at ##O## under the map ##F_{a,b}##."

Homework Equations



Equation of a circle of radius ##r## centered at ##(a, b)##: $$(x - a)^2 + (y - b)^2 = r^2$$
Equation of a circle of radius ##r## centered at the origin: $$x^2 + y^2 = r^2$$
Equation of a circle of radius 1 centered at the origin: $$x^2 + y^2 = 1$$

The Attempt at a Solution


[/B]
I've spent quite some time on this problem and I still can't see how to solve it. I understand by subsequent indications and further reading on wikipedia that the equation is the cartesian equation of an ellipse and that the exercise is a way of viewing the ellipse as an irregularly dilated or stretched circle. However, I don't see any rigorous, algebraic way of coming to that equation from the circle equation using the ##F_{a,b}## mapping, nor the other way around (e.g. using an inverse mapping ##F^{-1}_{a,b}##). Applying the mapping to ##u## and ##v## on the left-hand side doesn't even seem to make sense. I might be missing something obvious...

Thanks in advance for your help.

PS: there isn't any development on ellipses in Lang's book (at least not in the part where the exercise comes from or before) so a solution can't rely on anything else that what was stated in the problem, except basic notions of coordinates, distance between points and Pythagora's theorem.
 
Physics news on Phys.org
Use parametrisation.

Let u = a sin t and v = b cos t.
 
Stefk said:
To each point ##(x, y)## of the plane, associate the point ##(ax, by)##.

Equation of a circle of radius 1 centered at the origin: $$x^2 + y^2 = 1$$

These are the relevant bits.

The first bit means, whenever you see ##x##, write ##ax##, whenever you see ##y## write ##by## (you can write it ##x \to ax## and ##y \to by## or something like that).

Now apply that to the second bit quoted above and take it from there.