Find the amount of a vector acting in the direction of another vector.

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Homework Help Overview

The discussion revolves around a problem in a statics class that involves finding the component of a force acting along a specific axis. The original poster expresses confusion regarding the application of the parallelogram rule and the sine law as suggested by their professor and textbook, questioning why these methods are preferred over using right triangles for the solution.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind using the parallelogram rule and sine law, while suggesting that a right triangle approach could yield the same results. They express a desire to challenge the correctness of the textbook and professor's methods.

Discussion Status

Participants are engaged in exploring different methods for solving the problem, with the original poster seeking clarification on the preferred approach. There is an acknowledgment of the potential validity of both methods, but no consensus has been reached regarding the best approach to take.

Contextual Notes

The original poster references specific images to illustrate their points, which have been noted to be too large initially, prompting a request for resizing. The discussion includes the mention of vector decomposition concepts, although this is not fully resolved within the thread.

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Homework Statement



I have a problem in a statics class that asks to find the component of a force acting along an axis seen here http://i.imgur.com/aZ1vMIu.jpg?1.

Homework Equations





The Attempt at a Solution


The book and my professor say to use the parallelogram rule and then use sine law to find the solution like this http://i.imgur.com/dipBfjq.jpg?1 , but I do not see why it should be done this way; I understand that the axis are tilted slightly but I would think in order to solve this problem you would still use a right triangle rather than the parallelogram rule like this http://i.imgur.com/3Pazp0l.jpg?1 and I can turn the force into a vector and then find the component of the force onto the axis and I get the same answer that I would if I used right triangles like this http://i.imgur.com/naGp3us.jpg?1 . Now I'm assuming my professor and the book are correct(even though I would love to prove them wrong) so why would I use a parallelogram instead of a right triangle?
Also here is the answer in the back of the book http://i.imgur.com/5k4UaLC.jpg?1 .
 
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Your images are way too large. Please resize them to about 800 X 600 and repost them so that people will be able to see them without having to scroll across and from top to bottom.
 
Slartibartfest said:

Homework Statement



I have a problem in a statics class that asks to find the component of a force acting along an axis seen here http://i.imgur.com/aZ1vMIu.jpg?1.

Homework Equations





The Attempt at a Solution


The book and my professor say to use the parallelogram rule and then use sine law to find the solution like this http://i.imgur.com/dipBfjq.jpg?1 , but I do not see why it should be done this way; I understand that the axis are tilted slightly but I would think in order to solve this problem you would still use a right triangle rather than the parallelogram rule like this http://i.imgur.com/3Pazp0l.jpg?1 and I can turn the force into a vector and then find the component of the force onto the axis and I get the same answer that I would if I used right triangles like this http://i.imgur.com/naGp3us.jpg?1 . Now I'm assuming my professor and the book are correct(even though I would love to prove them wrong) so why would I use a parallelogram instead of a right triangle?
Also here is the answer in the back of the book http://i.imgur.com/5k4UaLC.jpg?1 .

If you have vectors ##\vec{u}## and ##\vec{v}##, you can decompose ##\vec{u}## into a component ##\vec{u}_{||}## that is parallel to ##\vec{v}## and a component ##\vec{u}_{\perp}## that is perpendicular to ##\vec{v}##. That is,
\vec{u} = \vec{u}_{||} + \vec{u}_{\perp}
\vec{u}_{||} = \left(\frac{\vec{u} \cdot \vec{v} }{\vec{v} \cdot \vec{v}} \right) \vec{v}
\vec{u}_{\perp} = \vec{u} - \vec{u}_{||}<br /> = \vec{u}- \left( \frac{\vec{u} \cdot \vec{v} }{\vec{v} \cdot \vec{v}} \right) \vec{v}
So, if you can compute the inner product of ##\vec{u}## and ##\vec{v}## you are almost done. This works in any number of dimensions.
 

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