Find the amount of work done against gravity in moving a 150kg rocket

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SUMMARY

The discussion centers on calculating the work done against gravity when moving a 150 kg rocket. The user applied the gravitational potential energy formula, resulting in an energy difference of 5.6 x 10^9 J between the Earth's surface and an orbital radius of 18,000 km. The textbook answer of 6 x 10^5 J is incorrect, as confirmed by other participants in the forum. The calculations provided by the user are accurate based on the established gravitational equations.

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Homework Statement
Find the amount of work done against gravity in moving a 150kg rocket from the surface of the Earth to 18000 km above the center of the Earth.
Relevant Equations
E = -Gmm/r
I started by calculating the energy at the Earths surface, which is just -G(150)(6 x 10^24)/(6400 x 10^3) = -0.9 x 10^10, and calculating the energy at the orbit radius, E = -G(150)(6 x 10^24)/(18000 x 10^3) = -3.4 x 10^9, then doing some subtraction we have -3.4 x 10^9 - (-0.9 x 10^10) = 5600 x 10^6 J. The answer provided in my textbook is 6 x 10^5 J which is clearly not what I got. Any tips?
 
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sdfsfasdfasf said:
Any tips?
Get a better textbook?
 
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Possible typo in the textbook. The answers section.
 
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So my answer is correct?
 
sdfsfasdfasf said:
So my answer is correct?
Yes.
 
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