Find the angle and the velocity of two cars after collision

Click For Summary
SUMMARY

The collision analysis of two cars on an icy parking lot reveals that after the collision, the combined velocity of the cars is 12.95 km/h. The first car, with a mass of 1000 kg traveling at 20 km/h, and the second car, with a mass of 800 kg moving at 15 km/h perpendicular to the first, slide together at an angle of 30.96 degrees. The calculations utilize momentum conservation principles in both x and y directions to derive the final velocity and angle.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Basic trigonometry, specifically tangent functions
  • Knowledge of vector addition in physics
  • Familiarity with unit conversions, particularly km/h to m/s
NEXT STEPS
  • Study momentum conservation in two-dimensional collisions
  • Learn about vector decomposition and its applications in physics
  • Explore the effects of friction on collision outcomes
  • Investigate real-world applications of collision analysis in automotive safety
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicle collisions and momentum conservation.

mmoadi
Messages
149
Reaction score
0

Homework Statement



Two cars are driving on an icy parking lot, searching for a free parking space. The first car has a mass m1= 1000 kg and traveling at a speed of 20 km/h, the second car has a mass of m2= 800 kg and drives perpendicular to the direction of the first car at a speed of 15 km/h. They are not aware of each other and crash, so that their cars slide together at an angle θ along previous direction of the first car.
- With what velocity will the two cars be moving immediately after the collision?
- Find the angle at which the two cars start moving?

http://www.slide.com/s/kqikbbPm1j8EewZiTRju4CCgaHODnfDF?referrer=hlnk

Homework Equations



p= mv
tan= opp/adj

The Attempt at a Solution



First part: With what velocity will the two cars be moving immediately after the collision?

x-direction: m(1)v(1) + 0= (m(1) + m(2))v(x) → v(x)= m(1)v(1) / (m(1) + m(2))
v(x)= 11.11 km/h
y-direction: 0 + m(2)v(2)= (m(1) + m(2))v(y) → v(y)= m(2)v(2) / (m(1) + m(2))
v(y)= 6.66 km/h

v²= v(x)² + v(y)²
v= 12.95 km/h

Second part: Find the angle at which the two cars start moving?

tan θ= v(y) / v(x)= [m(2)v(2) / (m(1) + m(2))] / [m(1)v(1) / (m(1) + m(2))]= m(2)v(2) / m(2)v(2)= 0.6
θ= 30.96 º

I really need to know if may calculations are correct.
Thank you for helping!:smile:
 
Last edited by a moderator:
Physics news on Phys.org
Yes, they're correct.
 
Thank you :smile: !
 

Similar threads

  • · Replies 29 ·
Replies
29
Views
4K
Replies
1
Views
1K
Replies
57
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
7
Views
2K
Replies
3
Views
2K
Replies
3
Views
7K