At what angle will the electrons leave the uniform electric field at the end of the parallel plates? Assume the plates are 4.9 cm long and E = 5.0 x 10^3 N/C.(adsbygoogle = window.adsbygoogle || []).push({});

*The answer to this question is -23 degrees.

So far what I have tried to do is find the position of the electron on the y-axis and then take the tangent of the x&y values. My answers so far have been off. The closest I've gotten so far is -12 degrees.

This is the equation I used:

y = [(qE) / (2m(V)^2)] * (x)^2

q= -1.6x10^-19 C

m= 9.1x10^-31 kg

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# Find The Angle of The Electron; Motion of Charges

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