Find The Angle of The Electron; Motion of Charges

[withthemotive]

At what angle will the electrons leave the uniform electric field at the end of the parallel plates? Assume the plates are 4.9 cm long and E = 5.0 x 10^3 N/C.

*The answer to this question is -23 degrees.

So far what I have tried to do is find the position of the electron on the y-axis and then take the tangent of the x&y values. My answers so far have been off. The closest I've gotten so far is -12 degrees.

This is the equation I used:

y = [(qE) / (2m(V)^2)] * (x)^2

q= -1.6x10^-19 C
m= 9.1x10^-31 kg

 

[Hootenanny]

Let's start again from the beginning.

What are the forces acting on the electron? Can you therefore determine the acceleration of the electron?

*Clarification: Does the question mention the orientation of the field/plates? Is the electric field directed vertically upwards/downwards or horizontally for example?

 

[withthemotive]

Yeah, the orientation of the plates is negative on bottom and positive on top.

 

[Hootenanny]

Yeah, the orientation of the plates is negative on bottom and positive on top.

Okay, thanks.

What are the forces acting on the electron? Can you therefore determine the acceleration of the electron?