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Find The Angle of The Electron; Motion of Charges

  1. Jan 17, 2009 #1
    At what angle will the electrons leave the uniform electric field at the end of the parallel plates? Assume the plates are 4.9 cm long and E = 5.0 x 10^3 N/C.

    *The answer to this question is -23 degrees.

    So far what I have tried to do is find the position of the electron on the y-axis and then take the tangent of the x&y values. My answers so far have been off. The closest I've gotten so far is -12 degrees.

    This is the equation I used:

    y = [(qE) / (2m(V)^2)] * (x)^2

    q= -1.6x10^-19 C
    m= 9.1x10^-31 kg
     
  2. jcsd
  3. Jan 18, 2009 #2

    Hootenanny

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    Let's start again from the beginning.

    What are the forces acting on the electron? Can you therefore determine the acceleration of the electron?

    *Clarification: Does the question mention the orientation of the field/plates? Is the electric field directed vertically upwards/downwards or horizontally for example?
     
  4. Jan 18, 2009 #3
    Yeah, the orientation of the plates is negative on bottom and positive on top.
     
  5. Jan 19, 2009 #4

    Hootenanny

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    Okay, thanks.
     
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