Find the angle required for a 3kg block to slide down an incline

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SUMMARY

The discussion centers on determining the angle required for a 3kg block to slide down a frictionless incline. Participants clarify that without friction, any non-zero angle will suffice for the block to begin sliding. The equations referenced include F=mg and Fnet=ma, which are fundamental in analyzing forces acting on the block. The consensus is that the problem may be misleading, as it implies a minimum angle when, in fact, any angle greater than zero will result in motion.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic trigonometry, specifically sine and cosine functions
  • Familiarity with the concept of friction and its absence in physics problems
  • Knowledge of free body diagrams to visualize forces acting on objects
NEXT STEPS
  • Study the effects of friction on inclined planes using static and kinetic friction coefficients
  • Learn about free body diagrams and how to apply them in physics problems
  • Explore the concept of acceleration on inclined planes and how to calculate it
  • Investigate the role of angles in projectile motion and their relationship to forces
USEFUL FOR

High school physics students, educators teaching mechanics, and anyone interested in understanding the dynamics of motion on inclined planes.

zippyzay165
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Homework Statement
Hello, I'm a high school student and relatively new to learning physics. I've gotten a question that I'm stumped on.
Relevant Equations
F=mg
Fnet = ma
physics234.png

This is a rough sketch of the model.
It is frictionless.
I originally tried simple right-angle trig (sin θ =opp/hyp), but that just ends up as sin θ = sin θ , as well as cos θ = cos θ.

I feel like there's also a way to manipulate dynamic equations around to equate something that is capable of finding θ , but I haven't been able to compose one that proves anything yet. I would appreciate any help, thank you!
 
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zippyzay165 said:
Homework Statement:: Hello, I'm a high school student and relatively new to learning physics. I've gotten a question that I'm stumped on.
Relevant Equations:: F=mg
Fnet = ma

View attachment 264178
This is a rough sketch of the model.
It is frictionless.
I originally tried simple right-angle trig (sin θ =opp/hyp), but that just ends up as sin θ = sin θ , as well as cos θ = cos θ.

I feel like there's also a way to manipulate dynamic equations around to equate something that is capable of finding θ , but I haven't been able to compose one that proves anything yet. I would appreciate any help, thank you!
It looks to me as though you should have been given a coefficient of static friction and asked to find the minimum angle at which it will slide. Without friction, any nonzero angle will do.
 
zippyzay165 said:
Homework Statement:: Hello, I'm a high school student and relatively new to learning physics. I've gotten a question that I'm stumped on.
Relevant Equations:: F=mg
Fnet = ma

View attachment 264178
This is a rough sketch of the model.
It is frictionless.
I originally tried simple right-angle trig (sin θ =opp/hyp), but that just ends up as sin θ = sin θ , as well as cos θ = cos θ.

I feel like there's also a way to manipulate dynamic equations around to equate something that is capable of finding θ , but I haven't been able to compose one that proves anything yet. I would appreciate any help, thank you!
Can you post what the question is? Are they asking to find the acceleration?
 
It's asking to find the minimum angle required for the block to move down when it's frictionless.
 
haruspex said:
It looks to me as though you should have been given a coefficient of static friction and asked to find the minimum angle at which it will slide. Without friction, any nonzero angle will do.
coefficient seems to be 0...so does that mean there's a range of answers then?
 
zippyzay165 said:
It's asking to find the minimum angle required for the block to move down when it's frictionless.
Then, as Haruspex pointed out, the answer is any angle greater than zero. If there is no friction, any tilt of the incline will make the block slide down, clearly. It is a strange question.
 
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