Find the average power of the crashed test car.

AI Thread Summary
In a crash test scenario, a car with a mass of 1734 kg traveling at 30.9 m/s comes to a stop in 0.8 seconds. To calculate the average power expended during the crash, the kinetic energy (KE) must be determined using the formula W = ΔKE, where the initial velocity is 30.9 m/s and the final velocity is 0 m/s. The power can then be calculated using P = W/t. The discussion highlights confusion regarding the correct application of equations and the determination of initial and final kinetic energy. Ultimately, the correct approach involves recognizing the initial velocity as 30.9 m/s and the final velocity as 0 m/s to find the average power.
pstrokeslibs
Messages
4
Reaction score
0

Homework Statement



In a crash test, a test car of mass 1734 kg is moving at a speed of 30.9 m/s (= 69.5 miles per hour) when it crashes into a wall. If the car comes to rest in 0.8 s, how much average power (in W) is expended in this process?

Homework Equations



P=W/t to find "P"
W=Fd to find "W"
F=ma to find "F"
v=d/t to find "d"
a=v/t to find "a"

The Attempt at a Solution



i think the problem gives us, time(t)=0.8s, mass of car(m)=1734kg, velocity(v)=30.9m/s. i already did it by all of those equation, but the answer still wrong, or it's because of my equation that wrong.. sorry for my poor english, I am an Asian exchange student here in the US, please help me :(

thank you! :)
 
Physics news on Phys.org
Well the energy it has is kinetic energy, which is being used in the 0.8 seconds.

So use P = W/t and get the power.
 
So we can use equation W=(delta)KE right? but what is the initial KE and final KE... I am sorry

should the initial velocity be 30.9m/s and the final velocity 0m/s?? I am going to use W=1/2m(finalvelocity^2-initialvelocity^2)

Thanks for help :D
 
Last edited:
pstrokeslibs said:
So we can use equation W=(delta)KE right? but what is the initial KE and final KE... I am sorry

should the initial velocity be 30.9m/s and the final velocity 0m/s?? I am going to use W=1/2m(finalvelocity^2-initialvelocity^2)

Thanks for help :D

Yes that would be it.
 
i got it now! thanks very much! but... the 30.9 is final velocity...
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top