Find the change of internal energy of the air.

Click For Summary

Homework Help Overview

The discussion revolves around calculating the change of internal energy of air within a car tire, initially at a pressure of 1.8 atm and a temperature of 293 K, which later increases to 2 atm due to friction during travel.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the internal energy formula U=3/2nRT and question the value of the fraction, considering the diatomic nature of the gases in air. There are attempts to apply the ideal gas law to find the number of moles (n) and to calculate the change in internal energy based on varying conditions.

Discussion Status

Some participants have provided guidance on using the ideal gas law and have pointed out potential issues with significant figures in the calculations. There is acknowledgment of differing results from the textbook, leading to further exploration of the calculations involved.

Contextual Notes

Participants note that some data in the problem is given to only two significant figures, which may affect the final answer. There is also discussion about the appropriate value to use for atmospheric pressure in calculations.

MaiteB
Messages
44
Reaction score
0

Homework Statement


A car rubber has the volume 50 liters when it is bloated in a pressur 1.8 atm and in a temperature 293 K. After some hours of journey as an effect of friction the pressure will become 2atm. Find the change of internal energy of the air inside the rubber (U)

Homework Equations


U=3/2nRT

The Attempt at a Solution


I thought to sue the formula U=3/2nRT, but I don't know the n.
 
Physics news on Phys.org
Don't forget the ideal gas law. Also, in the formula for U, are you sure the fraction is 3/2? Nitrogen and oxygen are diatomic gases.
 
TSny said:
Don't forget the ideal gas law. Also, in the formula for U, are you sure the fraction is 3/2? Nitrogen and oxygen are diatomic gases.
Ok but how can I find the U with this compound of gases like air?
 
TSny said:
Don't forget the ideal gas law. Also, in the formula for U, are you sure the fraction is 3/2? Nitrogen and oxygen are diatomic gases.
I am writing my solution: pV=nRT=>n=(1.8*10^5*0.05)/(8.31*293)=3.7
1.8/293=2/x=>x=325.5555
U= 5/2* 3.7*8.31*(325.56-293)=2500, but in my book the answer is 2537J
 
Looks good. Some of the data in the problem is given to only 2 significant figures. So, the textbook should have rounded the answer to 2 significant figures which agrees with yours.
 
  • Like
Likes   Reactions: MaiteB
If you use 1.01325 x 105 for atm you find a better number. Your calculation is correct.
 
  • Like
Likes   Reactions: MaiteB

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
Replies
3
Views
3K