Find the Charge Needed for a 1.20V Voltage at 5.0m

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Homework Help Overview

The discussion revolves around determining the charge needed on a small sphere to achieve a voltage of 1.20 V at a distance of 5.0 m. The subject area is electrostatics, specifically relating to voltage and charge interactions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relevant equations for voltage, with one suggesting V = kQ/r and another questioning the use of V = kQ/r^2. There is also a focus on the conversion of charge units from Coulombs to nanoCoulombs.

Discussion Status

Some participants have provided guidance on which equation to use and have clarified the meaning of variables involved. There is an ongoing exploration of unit conversion and the implications of the chosen equations, but no consensus has been reached on the final approach.

Contextual Notes

Participants note that the distance referred to as 'radius' by the teacher is essentially the same as the distance in the problem. There is also mention of potential conversion errors that may arise during calculations.

NegaChin
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We wish to place a small charged sphere at a distance of 5.0 m from a point in space such that the voltage at that point is 1.20 V. How much charge should be on the sphere (in nC)?
 
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What have you tried? What equations do you think you might need?
 
I've tried V = kQ/r and V = kQ/r^2. If either of those are right, please respond, and if one of them is, then I feel I'm having conversion errors.
 
r is essentially the distance (my teacher has been using 'radius' all this time)
 
That second equation you're using with the r^2, don't use that one. The one you want to use is the first one. k is a constant and r is the radial distance (the question specifies that as 5.0m). If the voltage at that point is 1.20V, and you know the value of k and r, then just solve for Q.
 
The answer comes out in Coulombs, right? How would I convert that to nanoCoulombs? Just multiply by 10^-9?
 
Yea, in coulombs.

u know 1 [nC] = 1E-9 [C]
say you get x coloumb
x [C] * 10^-9 [?]/1[?] ??
you must learn to use those SI units
 

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