Find the charge of the oil drop

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SUMMARY

The charge of the oil drop is calculated to be -1μC using the equation E = σ / 2ε, resulting in an electric field (E) of 1000 N/C. The force balance equation ΣF = 0 leads to the conclusion that the electric force (Fel) equals the negative of the gravitational force (mg). The negative charge indicates that the direction of the electric force is towards the plate, while gravity acts downwards. The sign of gravity (g) is considered negative in this context.

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Homework Statement


screenshot_30.png


Homework Equations


E = σ / 2ε
E = Fel / Q

The Attempt at a Solution


E = σ / 2ε
= 17.7*10-9 /(2*8.85*10-12)
E =1000 N/C
ΣF = 0
Fel + mg = 0
Fel = - mg
1000 * q = - 10-3
q = - 10-3 / 1000 = 10-6 C
= -1μC
Could somebody check my answer please ?
 

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If the charge of the drop is negative, is the direction of the electric force towards or away from the plate? What about the direction of gravity, towards or away?
 
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Which way is positive ? Then think about the sign of ##g##
 

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