Find the coefficient of friction between block and surface

[shivu30198]

Homework Statement

A block of mass 2.4 kg sliding along horizontal rough surface is traveling at a speed 4.1 m/s when strikes a massless spring and compresses spring a distance 3.7 cm before coming to stop. If the spring has stiffness constant 714.3 N/m, find coefficient of friction between block and surface.

Relevant Equations

Wfr= umgcos

Ff.x= mv2/2 - kx2/2
umgx= mv2/2-kx2/2
u= mv2-kx2/2mgx =

 

[erobz]

Homework Statement: A block of mass 2.4 kg sliding along horizontal rough surface is traveling at a speed 4.1 m/s when strikes a massless spring and compresses spring a distance 3.7 cm before coming to stop. If the spring has stiffness constant 714.3 N/m, find coefficient of friction between block and surface.
Relevant Equations: Wfr= umgcos

Ff.x= mv2/2 - kx2/2
umgx= mv2/2-kx2/2
u= mv2-kx2/2mgx =

What is your question?

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[Aurelius120]

Use energy conservation.
Since block comes to rest:
$(KE)_{initial}=\text{ Energy stored in spring }+\text{ Energy lost to friction }$

 

[Aurelius120]

But you seem to know that, so are you asking us to do the mathematics?

 

[haruspex]

umgx= mv2/2-kx2/2
u= mv2-kx2/2mgx

Some mistakes in that last step.