(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A car giving a turn on a curve with 88m of radius, traveling at a speed of 95km/h, the curve is perfectly banked for a car traveling at 75 km/h, meaning that the curve has an angleθof 26.7º.

2. Relevant equations

μ = ?

r = 88m

v = 26.38 m/s

θ = 26.7º

Ff =μ · g · m

Fc = m (v^2/r)

Fg = m · g

3. The attempt at a solution

Hoping that The FBD is right, I came up with

ΣFy = FNy - mg - Ffy = 0

= FN cosθ - mg - FNμ f sinθ = 0

FN cosθ -FNμ f sinθ = mg

FN (cosθ -μsinθ) =mg

FN = (mg)/(cosθ -μsinθ)

then I used theFN = Fc, which I substituted to(mg)/(cosθ -μsinθ) = m(v^2/r).

And then, for what I understand, masses cancel each other.

g/(cosθ -μsinθ) = (v^2/r)

The problem is that I am stuck, I do not know how to transform the equation for solving fornor if the procedure I've followed this far is right. (seems right to me)μ.

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# Homework Help: Find the Coefficient of friction on a banked curve.

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