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**1. Homework Statement**

For the circuit shown in the figure, find the current through and the potential difference across each resistor.

http://session.masteringphysics.com/problemAsset/1169464/1/jfk.Figure.23.P60.jpg

**2. Homework Equations**

V=I(amps)/R(ohms) and Req=R1+R2+R3.....

**3. The Attempt at a Solution**

Rearranging the circuit:

R(8ohm) and R(24ohm) are parallel so (1/8+1/24)^-1=6ohm

that created a series of R(6ohm)+R(6ohm) so R6+R6=R(12ohm)

now I have the first circuit R(4ohm) in parallel with R(12ohm) and R(24ohm)

(1/4+1/12+1/24)^-1=2.67ohm for equivalent resistance for the entire circuit

24V=I*2.67ohm

I=9Amps

across the 4ohm resistor the current is? I=9A because the current is the same or is it 9A divided across the 3 parallel resistors?

I'm either getting it wrong because I put the 4ohm by itself (before the junction correct?) or if it's in series with the 2 6ohm resistors then that's my error but I've definitely tried it 4 different ways and am getting something wrong.

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**