Find the current by adding the resistances

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SUMMARY

The discussion focuses on calculating current and voltage in a circuit involving resistors and capacitors. It establishes that the three resistors are in series, allowing for the current to be determined by summing the resistances and applying Ohm's Law. The voltage drop across each resistor can then be calculated, which is essential for determining the voltage across the capacitors. Additionally, in parallel circuits, the current in each branch can be found, facilitating voltage calculations across the capacitors.

PREREQUISITES
  • Understanding of Ohm's Law
  • Knowledge of series and parallel circuits
  • Familiarity with capacitors and their behavior in circuits
  • Basic circuit analysis techniques
NEXT STEPS
  • Study series and parallel circuit configurations in detail
  • Learn about calculating voltage drops across resistors
  • Explore capacitor charging and discharging principles
  • Investigate advanced circuit analysis methods, such as mesh and nodal analysis
USEFUL FOR

Students in electrical engineering, hobbyists building circuits, and anyone seeking to understand the fundamentals of circuit analysis involving resistors and capacitors.

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Homework Statement




http://i260.photobucket.com/albums/ii10/alexlovely77/af.jpg

Homework Equations



q=cv

The Attempt at a Solution



i just want help with 1 of the 3 (anyone...)
so the first one...the current thru the capacitors is 0
then u have to find voltage right?
but how do u find the voltage thru those resistors?
r the 3 resistors in series? or do the capacitors make them not in series?
 
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In the first, the resistors form a simple series circuit. Find the current by adding the resistances, then apply Ohms law. Once you have the current you can find the voltage drop across each resistor. This will give you the voltage seen by the capacitors.


In the second you can easily find the current in each branch of the parallel circuit. You can then find the voltage at each end of the cap. The difference is the voltage used to find the charge.
 

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