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Find the derivative of:y= (ax + sqrt of x^2 +b^2)^-2

  1. Oct 9, 2007 #1
    The question is Find the derivative of:
    y= (ax + sqrt of x^2 + b^2)^-2

    I got this

    -2(ax + sqrt of x^2 + b^2)^-3 *(a+ 2/ sqrt of x^2 + b^2) *2x

    but i dno if this is right, can someone help me.
     
  2. jcsd
  3. Oct 9, 2007 #2
    Yea I got the same thing minus 2/ sqrt of x^2 + b^2

    It should be 1/(2*biggiantmess^1/2)

    or u^1/2 = 1/(2*u^1/2)
     
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