- #1

Arshad_Physic

- 51

- 1

## Homework Statement

Consider four vectors ~F1, ~F2, ~F3, and ~F4,

where their magnitudes are

F1 = 50 N,

F2 = 29 N,

F3 = 27 N, and

F4 = 58 N.

Let

theta1 = 150 degrees,

theta2 = -140 degrees,

theta3 = 24 degrees, and

theta4 = -66 degrees, measured from the positive x axis

with the counter-clockwise angular direction

as positive.

What is the magnitude of the resultant vec-

tor ~F , where ~F = ~F1 + ~F2 + ~F3 + ~F4? Answer

in units of N.

I found the answer to his part:

-17.259 i and -35.645 j , with a magnitude of 39.604

My online homework accepted this answer :)

........BUT.....

*(part 2 of 2)*

What is the direction of this resultant vector

~F?

Note: Give the angle in degrees, use coun-

terclockwise as the positive angular direction,

between the limits of -180 degrees and +180 degrees from

the positive x axis. Answer in units of degrees.

## Homework Equations

I tried doing: tan θ = -35.645/-17.259 - θ=64.164 °

## The Attempt at a Solution

I tried doing: tan θ = -35.645/-17.259 - θ=64.164 ° - The answer proved out to be wrong.....And thus I can now score a maximum of 93% on this question! :(

I have NO IDEA as to how to solve it - I looked in google, but to no avail......All help would be appreciated! :)

Thanks

Arshad