Find the domain and rainge of this function (rational fn)

  • Thread starter Thread starter skyturnred
  • Start date Start date
  • Tags Tags
    Domain Function
Click For Summary
SUMMARY

The function f(x,y) = -3y / (x² + y² + 1) has a domain of R², as there are no values of x or y that make the denominator zero. The range of the function is definitively from -3/2 to 3/2, as confirmed by the professor, due to the nature of the function's output being constrained by the maximum and minimum values of -3y divided by a positive quantity. The misunderstanding arises from the incorrect assumption that the range could be R³, which is not applicable since the function maps from R² to R¹.

PREREQUISITES
  • Understanding of rational functions
  • Knowledge of domain and range concepts
  • Familiarity with multivariable calculus
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of rational functions in multivariable calculus
  • Learn about the concept of limits and continuity in functions
  • Explore the method of finding ranges for multivariable functions
  • Investigate graphical representations of functions to visualize domain and range
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable functions, educators teaching rational functions, and anyone seeking to deepen their understanding of domain and range in mathematical contexts.

skyturnred
Messages
117
Reaction score
0

Homework Statement



Find domain and range of

f(x,y)=[itex]\frac{-3y}{x^{2}+y^{2}+1}[/itex]

Homework Equations





The Attempt at a Solution



It's quite obvious the the domain is R[itex]^{2}[/itex], because there are no possible values of x or y that would make the denominator 0.

But as for the range, my prof said that the range is from -3/2 to 3/2.

I can't figure out why. In my opinion, the range should be R[itex]^{3}[/itex], shouldn't it? I mean, there is no value y that would make the function not make sense. Also, x isn't even in the numerator and since we already accounted for it in the denominator, there is also no value x that would make the function not make sense. So how isn't the range R[itex]^{3}[/itex]?

Thanks in advance for the help.
 
Physics news on Phys.org
The range isn't R^3 because the function f: R^2->R^1.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
24
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
7
Views
2K