MHB Find the domain of the function .

Thread starter Riwaj
Start date Oct 22, 2017
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Domain Function

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To find the domain of the function f(A) = (1 + sinA) / (1 - sinA) given its range is {0, 1, 3}, the equation f(A) = 0 leads to solving 1 + sinA = 0, resulting in sinA = -1. For f(A) = 1, the equation simplifies to 1 + sinA = 1 - sinA, giving sinA = 0. Lastly, for f(A) = 3, the equation 1 + sinA = 3(1 - sinA) leads to sinA = 2/4 or sinA = 1/2. The domain is thus determined by the values of A that satisfy these conditions. The analysis reveals the specific angles corresponding to these sine values, defining the complete domain of the function.

Oct 22, 2017

Riwaj

1) Given that the range of function f(A) = \frac{1 + sinA}{1 - sinA} is { 0,1,3} . Find the domain of the function .

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Oct 22, 2017

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Riwaj said:

1) Given that the range of function f(A) = \frac{1 + sinA}{1 - sinA} is { 0,1,3} . Find the domain of the function .

Let f(A) = 0 and solve for A.

Do the same for 1 and 3.

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