Find the electric field at the point given

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SUMMARY

The discussion focuses on calculating the electric field at a specific point due to two point charges: +50 µC and -10 µC, separated by distances of 0.45 m and 0.30 m, respectively. The relevant equation for electric field intensity, E = kq/r², is emphasized, where 'k' is Coulomb's constant. The solution involves vector addition of the electric fields produced by each charge at the point of interest. The correct distances for each charge must be used to accurately compute the electric field contributions.

PREREQUISITES
  • Understanding of Coulomb's Law and electric fields
  • Familiarity with the equation E = kq/r²
  • Knowledge of vector addition in physics
  • Basic concepts of point charges and their interactions
NEXT STEPS
  • Study the derivation of electric field intensity due to point charges
  • Learn about vector addition of electric fields
  • Explore the implications of charge polarity on electric field direction
  • Investigate the concept of superposition in electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone seeking to understand electric field calculations involving multiple point charges.

xxabr
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Homework Statement



Find the electric field at the point given, x.

(+50uC)-------0.45m---- (-10uC) -----0.30m----- ( x )


Homework Equations


E= kq/r^2

Maybe, E= Fe/q and Fe= kq1q2/r^2


The Attempt at a Solution



q1= 50x10^-6
q2= -10x10^-6
q3= ?

I have no idea what equation to start with or where to start.
If I were to use E=kq/r^2
I don't know which charge to use for 'q'
Please help, thanks.
 
Last edited:
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Use vector addition of Electric field intensity.
The electric Field at x will be
Ex = E1 + E2
where E1 and E2 are the electric field intensity vectors due to 50 and -10uc resp.
 
Alright so,
If I use E=kq/r^2 for 50x10^-6C ... R would be 0.45m
and for -10x10^-6C ... R would be 0.30m?
 
xxabr said:
Alright so,
If I use E=kq/r^2 for 50x10^-6C ... R would be 0.45m
and for -10x10^-6C ... R would be 0.30m?

No and Yes.
Check your book where you derived electric field intensity due to a point charge. Find out what was 'r' there
 

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